A roller 2 m long has a diameter 140 cm. To level a play ground it takes 350 complete revolutions. Determine the cost of levelling the playground at the rate of 75 paise per square meter.

Diameter of a roller = 140 cm

Radius of the roller :

Thus, the radius of the roller = 70 cm

Height of roller = 2 m = 2×100 cm = 200 cm

Curved surface area of roller = 1 revolution

The curved surface area of this roller :

Thus, the curved surface area of the roller = 87920 cm²

Number of revolutions that needs to be done to level the ground = 350

Distance the roller will travel to get leveled :

Thus, to level the playground the distance the roller should cover = 539600 m

Cost of covering one square meter of land = 75 Paise

Cost of covering 539600 m of land :

▪︎The cost of leveling the playground = 404700 Rs

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: idk wbu

step-by-step explanation: