Find the sum of all numbers from 150 to 200 which are divisible by7​

Step-by-step explanation:

The sum is 1225

Solution : 

The numbers from 150 to 200 divisible by 7 are 154,161 ,168,…., 196

Here, a=154,d=7a=154,d=7 and tn=196tn=196

tn=a+(n−1)dtn=a+(n-1)d …(Formula )

∴196=154+(n−1)×7∴196=154+(n-1)×7 …(Substituting the values )

∴196−154=(n−1)×7∴196-154=(n-1)×7

∴427=n−1∴427=n-1 ∴n−1=6∴n-1=6 ∴n=7∴n=7

Now, we find the sum of 7 numbers.

Sn=n2[t1+tn]Sn=n2[t1+tn] ...(Formula )

=72[154+196)=72[154+196)

=72×350=72×350

=7×175=7×175

=1225

asdfghkl

step-by-step explanation:

asdfghkl

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068