There are 24 spaces on the Wheel of Fortune spinner. There are two bankrupt and one lose a turn section. What is the probability that you spin bankrupt or lose a turn on your turn? Experimental or Theoretical?

8.33%

Step-by-step explanation:

2÷224÷2=112

We know that

112

is the same as

1÷12

Then using

Long Division for 1 divided by 12

gives us

0.08333

Converting our number to a percentage:

0.08333×100

=8.33%

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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