The width of a rectangle is 32 inches. The width of the rectangle decreased by 8 inches and its length also changed. The area of the rectangle remains the same, 1,440 square inches. What is the new length of the rectangle?

60 in

Step-by-step explanation:

Area = length x width

Area is constant at 1440 in^2

For first rectangle: W1 and L1

For second rectangle: W2 and L2

W1 = 32 in

W2 = W1 - 8 in = 24 in

1440 in^2 = L1 x 32 in = L2 x 24 in

L1 = 45 in

L2 = 60 in

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)