I honestly forgot how to solve this ​

c must be -4

Step-by-step explanation:

x^2 - 5x + c = 0 is a quadratic whose coefficients are a = 1, b = -5 and c = c.

The discriminant is b^2 - 4ac, and we know that b^2 - 4ac = 41.

Substituting -5 for b and 1 for a, we get:

(-b)^2 - 4(1)(c) = 41, or 25 - 4c = 41, or -4c = 16.  Thus, c must be -4, and the quadratic is

x^2 - 5x - 4

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

answer: sine

step-by-step explanation: