How do i make 2 ( x + 3 ) into a no solution problem?

By making x = -3

Step-by-step explanation:

If X was -3 then -3 plus 3 equals 0, and 2 multiplied by 0 is 0, so the problem will have no solution.

Hope this helps! :)

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.