An object is launched at 24.5 meters per second from a platform that is 68.6 meters tall. The equation for the object's height in meters, h, at seconds after the launch is -4.9 + 2 + 24.5t + 68.6 •To find the number of seconds it will take the object to hit the ground after it is thrown, h must be set equal to 0: True or False?
•If h is set equal to 0, then t = 0 is a solution to the equation: True or False?
•The object will hit the ground at t=7 seconds: True or False?​

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.