I WILL GIVE YOU 20 POINTS AND MAKE YOU THE BRAINIEST, IF YOU ANSWER THIS CORRECTLY The lengths of the diagonals of a rhombus are 4x and 6x. What expression gives the perimeter of the rhombus?

Expression gives the perimeter = 4x√17

Step-by-step explanation:

∵ The diagonals of the rhombus ⊥ to each other and

  bisects each other

∴ Half the longest diagonal = 8x/2 = 4x

∴ Half the shortest diagonal = 2x/2 = x

Use Pythagoras theorem to find the length of the side of the rhombus

∴ The length of the side = √[(4x)² + (x)²] = √[16x² + x²] = √(17x²)

∴ S = x√17

∵ Perimeter of the rhombus = 4 × S

∴ P = 4 × x√17 = 4x√17

step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb