A weight of 6 lb stretches a spring a distance of 12 in. Find the constant k for the spring.

6 Ib

Step-by-step explanation: 12-6=6

Let F = the force (6 lbs) and x be the distance that the spring is stretched (12 inches).

F = kx

6 lb = k*(12 in.)

6/12 = k = 0.5 lb/in.

answer: it's d

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2