In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

291in^2

Step-by-step explanation:

Using the formula

Area of the triangle = 1/2absin theta

A = 1/2ijsin<K

Given

i = 74in

j = 23in

<K = 20 degrees

Area = 1/2 * 74*23sin20

Area = 37*23sin20

Area = 852sin20

Area = 291.059in^2

Hence the area of the triangle to nearest square inch is 291in^2

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;