Two balls are picked in succession without replacement -4 white balls and 5 green balls let Y be the random representing the number of green balls. Find the value of the random variable Y.

If Y represents the number of green balls then it can have values from 0- 5

that is it can have all the value  0,1,2,3,4 and 5.

The probability of getting both balss green without replacement is 0.27778

Step-by-step explanation:

If the balls are not replaced then this is the dependent event .

The probability of getting the first ball is given be = 5/9

where 5 is the number of green balls and 9 is the total number of balls.

The probability of getting the second ball green given that first is also green is  = 5/9* 4/8= 20/72= 0.2778

If Y represents the number of green balls then it can have values from 0- 5

that is it can have all the value  0,1,2,3,4 and 5.

0 means there can be no green balls or white balls.

1 means there can be one green ball.

2 means there can be 2 green balls and so on.

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.