Your friend says that the table represents an exponential function because y is multiplied by a constant factor. Is your friend correct? Explain. A. Yes. Because y is multiplied by a constant factor, the function is exponential.
B. Yes. Because y increases by greater amounts as x increases, the function is exponential.
C. No; Because y is multiplied by a constant factor, the function is not exponential.
D. No; Because x increases by different amounts, the function is not exponential.
x: 0,1,3,6
y: 2,10,50,250

C.No; Because y is multiplied by a constant factor, the function is not exponential.

Step-by-step explanation:

For a set of number to be exponential, there is need for it to show a logical increase of a given time frame when the set of number is multiplied by a constant factor. In the table given, though the Y function is multiplied by a constant factor, the increase of the function is irregular so therefore cannot be said to be exponential.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer

b. they are parallel and will never intersect.