HELP ANSWER 6,8,9!! WILL MARK BRAINIEST

please show work too!!!

Step-by-step explanation:

6). Since, m∠JMN = 90° [Given]

    And m∠JMK + m∠NMK = m∠JMN

    m∠JMK = m∠JMN - m∠NMK

                  = 90° - 28°

                  = 62°

    From the other figure,

    m∠STR + m∠STP = 180° [Linear pair of angles]

    m∠STR = 180° - m∠STP

                  = 180° - 118°

                  = 62°

    Therefore, mJMK = m∠STR = 62°

    And m∠JMK ≅ m∠STR

8). Since, BF is the angle bisector of ∠AFC,

    ∠AFB ≅ ∠BFC [By angle bisector theorem]

    ∠CFD ≅ ∠BFC [Given]

    Therefore, ∠AFB ≅ ∠CFD [Transitive property of equality]

9). AG is the bisector of CD,

    Therefore, CE ≅ DE (1)

    IJ is the bisector of CE,

    Therefore, CK ≅ KE (2)

    BH is the bisector of ED,

    Therefore, EF ≅ FD (3)

    Since, CE ≅ DE [Given as (1)]

    (CK + KE) ≅ (EF + FD)

    2(KE) ≅ 2(EF) [Given in properties (2) and (3)]

     KE ≅ EF

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is: