Find the area of a vertical cross section through the centers of the bases of a cylinder with height of 27 inches and a circumference of about 47.1 inches. Use 3.14 for π.

405 in^2

Step-by-step explanation:

Given data

Height= 27in

Circumference= 47.1 in

let us find the radius and the diameter of the base of the cylinder

from

C=2πr

47.1= 2*3.142*r

47.1= 6.284r

r= 47.1/6.284

r= 7.5 in

Diameter= 2r

D= 7.5*2

D= 15in

Hence the area of the cross-section

=H*D

=27*15

=405 in^2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b