What is the equation of the line that passes through the point (8, 4) and has a slope
of 3/2?

y = (3/2)x - 8    slope-intercept form

3x - 2y = 16      standard form

Step-by-step explanation:

Use the point-slope form of a line to do this problem.

In your case

So. y - 4 = 3/2 ( x - 8)  

multiply thru by 2

2y - 8 = 3(x - 8)

2y - 8 = 3x - 24

2y = 3x - 16

y = (3/2)x - 8    slope-intercept form

3x - 2y = 16      standard form

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0