≠A student took a system of equations, multiplied the first equation by and the second equation by , then added the results together. Based on this, she concluded that there were no solutions. Which system of equations could she have started with?

C. 3x+6y=9  and-2x-4y=4

Step-by-step explanation:

Given

Steps:

The attachment completes the question

(a): -2x+4y=4 and -3x+6y=6

Multiply by 2:

Multiply by 3:

Add together

B. 3x+y=12  and -3x+6y=6

Multiply by 2:

Multiply by 3:

Add together:

C. 3x+6y=9  and-2x-4y=4

Multiply by 2:

Multiply by 3:

Add together:

This is the equation the student could have used because 0 = 30 means the equation has no solution.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine