Shirley went shopping in a mall. She reached the mall 12.5 minutes later than her usual time. While returning she took 20 minutes more than twice her usual time to reach home. If the usual time she takes to reach the mall is 40 minutes, find the total number of minutes Shirley spent going and coming back from the mall.

Total time Shirley spent  going and coming back from the mall= 152.5 minutes

Step-by-step explanation:

Usual time it takes to reach mall from home = 40 minutes

New time she took to reach the mall=12.5 minutes later than her usual time

= 40 minutes + 12.5 minutes= 52.5 minutes

New time she took to reach home ( lets assume she followed the same route as coming from home in which she spends 40 minutes) =20 minutes more than twice her usual time to reach home.=20 minutes + 2(40)= 20 minutes  + 80 minutes

=100 minutes

Total time  going and coming back from the mall =52.5 minutes  +100 minutes = 152.5 minutes

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

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step-by-step explanation: