A. Draw a rectangle with an
area of 39 squares, and
perimeter of 32 units.
a

It has side lengths of 3 and 13

Step-by-step explanation:

If it has an area of 39, then let the sides be x and y: thus we get the two relationships:

xy=39

2(x+y)=32

From the second equation, you get x+y=16. Now, rearrange to get y=16-x. You can now plug this into the first equation:

x(16-x)=39 -> 16x-x^2=39 -> x^2-16x+39=0 -> (x-3)(x-13)=0

This implies that x=3, or x=13, which further implies that the side lengths must be 3 and 13.

only 10/60 isn't equivalent

hope this : )

you can't solve x because it is 2 linear equation and you only have one equation