Ax^2+bx+c is the first degree polynomial of x which of these letters equal zero?

First degree polynomials means that the maximum power x is raised up to that does not have a coefficient 0 is 1. And here we have a term ax^2 which means it could not be a first degree polynomial if a has a positive or negative value. Thus, letter a in this case should be 0 in order for this to be a first degree polynomial of x.

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.