Three sides of a fence and an existing wall form a rectangular enclosure. the total length of a fence used for the three sides is 240 ft. let x be the length of two sides perpendicular to the wall as shown. write an equation of area a of the enclosure as a function of the length x of the rectangular area. then find the value(s) of x for which the area is 5500 ft^2.
i i x i i x existing wall x is the shorter wall. the existing wall is longer than the one across from it, i tried to make it look like that in the picture.

values of x = 30.85, 89.16 ft

Step-by-step explanation:

Let length of two sides perpendicular to the wall be x ft and length of the wall is y ft.

area A of the enclosure will be A = xy

Since area of the enclosure = 500 square feet

xy = 5500 ------(1)

Length of the three sides has been given as 240 ft.

2x + y = 240

y = 240 - 2x ------(2)

Now we put the value of y from equation 2 to equation 1

x(240 - 2x) = 5500

240x - 2x² = 5500

Now we divide this equation by 2

120x - x² = 2750

x² - 120x = - 2750

x² - 120x + 2750 = 0

x =

  =

  =

  =

x = 30.85, 89.16 ft

y = 178.28, 61.69 ft

If the wall is shorter than other sides then the value of x will be 89.16.

4038

step-by-step explanation:

pleaze mark brainliest!

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step-by-step explanation: