I really need help with this

A+6+A = 20

A = 7

Step-by-step explanation:

J = number of problems Juana completed

A = number of problems Andy completed

J+A=20

J = A + 6

Replace J with A+6 in the first equation

A+6+A = 20

2A +6 = 20

Subtract 6 from each side

2A +6-6 = 20-6

2A =14

Divide by 2

2A/2 = 14/2

A = 7

7

Step-by-step explanation:

set up your two equations.

j + a = 20. equation 1

j = a + 6. equation 2

since you know that j = a + 6, you can substitute a + 6 into the place of j. this is because you want to isolate a in order to find out how many problems andy completed.

j + a = 20

a + 6 + a = 20

now solve.

2a + 6 = 20

2a = 14

a = 7

andy has completed 7 problems. if juana completed 6 more than andy, then she has completed 13. 13 + 7 = 20.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: