Two students, Abby and Melissa go for a walk. Abby begins walking 30 seconds earlier than Melissa . -Abby walks at a speed of 8 feet per second.
-Melissa walks at a speed of 9 feet per second.

Abby had been walking for BLANK seconds when both students had walked exactly the same distance. (round to the nearest whole)
please help me

270 seconds

Step-by-step explanation:

Melissa's time = x seconds

Abby's time = (x + 30) seconds

Abby walks at a speed of 8 feet per second, and Melissa walks at a speed of 9 feet per seconds.

But, speed =

For Abby,

8 =

distance = 8(x + 30) ................. 1

for Melissa,

9 =

distance = 9x ............. 2

From equations 1 and 2, for the same distance;

8(x + 30) = 9x

8x + 240 = 9x

x = 240 seconds

Abby's time = (x + 30)

                    = (240 + 30)

                    = 270 seconds

So that Abby has been walking for 270 seconds when both students had walked exactly the same distance.

based on context clues you gave i'm assuming the answer would be c.

i don't even know man. edge inuity be messing with us. i had to ask a question too.