Find the area of the shape using Pythagoras Theorem please

122.09 (the answer may change depending on how many decimals you need if you need more or less just follow the steps using however many decimals)

Step-by-step explanation:

to get the other triangle side do 18-11= 7

then use the Pythagoras theorem to solve for the other side so 7^2+b^2=11^2

49+b^2= 121

121-49= b^2

72=b^2

b= 8.48(simplified)

then use that side to get the area of the rectangle:

8.42×11=92.62

then get area of the triangle:

1/2(8.42×7)=29.47

add the 2 areas to get total area:

92.62+29.47=122.09

x intercept = (-1,0)   (4,0)

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!