Point F on the coordinate grid is reflected across a line to create point F’. Then, points E, F, and F’ I connected to create a triangle. kari says Point E must be on the perpendicular bisector of the line FF’, regardless of the line across which point F was reflected. enter a equation of a line Across which F could be reflected to support Kari claim or enter the equation of a line across which F could be reflected a show that kari’s claim is incorrect.

y = 2

y = 0

Step-by-step explanation:

From the given information:

a)

Let assume we choose y = 2 as the line

Then F' = (-3 , -1) from the missing graph

So, the perpendicular bisector would be the line y = 2

Thus since E = (2,2), this line passes through E

b)

Here if we choose y = 0 as the line

Then F' = (-3,-5) from the missing graph

Thus, the perpendicular bisector would be  the line y = 0

Note: since E = (2,2) this line does not pass through E

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1