The exterior angles of a quadrilateral have measures of $72\degree,\ 58\degree,\ 2x\degree,$ and $3x\degree$ . Find the value of $x$ .

46degrees

Step-by-step explanation:

The sum of angles of exterior angles of a quadrilateral is 360 degrees

Hence;

72 + 58+2x+3x  = 360

130 + 5x  = 360

5x = 360-130

5x = 230

x  =230/5

x = 46 degrees

Hence the vale of x is 46degrees

i used to know but i learned it a long time ago sorry

step-by-step explanation:

if x = 1, then the answer is 3.5