When throwing fair dice, all six faces of each die are equally likely. There are thirty–six total possible outcomes, any of the six faces of die A can be matched with any of the six faces of die B. What is the probability the sum of the pips, spots, on the two faces is at least 9? 4/36=0.111

11/36=0.306

10/36=0.278

6/36=0.167

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

might be the correct answer will be question number 2