A rectangle measures 8.5 cm by 10.7 cm both correct to 1 decimal place. Calculate the upper bound of the perimeter of the rectangle​

The perimeter of the rectangle = 38.4cm

Step-by-step explanation:

Explanation:-

Given that the length of the rectangle(l) = 8.5cm

The width of the rectangle(w) = 10.7cm

The perimeter of the rectangle

                 P = 2(l+w)

                P = 2( 8.5 + 10.7)

                P = 2 ×19.2 = 38.4 cm

The perimeter of the rectangle = 38.4cm

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

c

step-by-step explanation: