(x^2+3x^2-kx-24)÷(x+3) what's the value of k??​

-4

Step-by-step explanation:

since x+3 is a factor of the polynomial (x^2+3x^2-kx-24), then;

x+3 = 0

x = -3

Substitute x = -3 into the polynomial

x^2+3x^2-kx-24 = 0

(-3)^2+3(-3)^2-(-3)k-24 = 0

9 + 27 + 3k - 24 = 0

36-24 + 3k = 0

12 = -3k

k = -12/3

k = -4

Hence the value of k is -4

step-by-step explanation:

the true ones are a b and d

16 is the absolute value

step-by-step explanation: