There are two numbers whose 400 powers are equal to 9^1000. In other words, there are two numbers that can replace x in the equation x^{400} = 9^{1000},making the equation true.

Find the smaller of the two numbers.

x+14

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116