The polygon Q(3, 2), R(6,5), S(6, 2) undergoes the transformation:
(x, y) → (4x, 4y). Name the coordinates
of the image points.
A Q'(3, 2), R'(6,5), S'16, 2)
B Q'(7,6), R'(10, 9), S'(10,6)
C Q'(12, 8), R'(24, 20), S'(24, 8)
D Q'(-1, -2), R'(2, 1), S (2,-2)

Q' (12,8) , R'( 24,20) and S' (24,8)

Step-by-step explanation:

Here, we want to get the coordinates of the image after dilating the pre-image by a scale factor of 4

What we have to do here is to multiply each of the coordinate on the pre-image by 4

We have this as;

Q' = (4*3, 2 * 4) = (12,8)

R' = (4*6, 4*5) = (24,20)

s' = (4*6, 4*2) = (24,8)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet