An artist combines copper and other metals to make bronze. A bronze sculpture of a dolphin contains 43 g of copper for every 7 g of other metals. A bronze
sculpture of a bird contains 83 g of copper for every 17 g of other metals.
Which sculpture is more coppery? Explain.
plsss help this test is due tmr

The dolphin statue is 86% copper, while the bird statue is 83% copper, making the dolphin sculpture more coppery.

Step-by-step explanation:

Since an artist combines copper and other metals to make bronze, and a bronze sculpture of a dolphin contains 43 g of copper for every 7 g of other metals, while a bronze sculpture of a bird contains 83 g of copper for every 17 g of other metals, to determine which sculpture is more coppery the following calculation must be performed:

Dolphin:

43 + 7 = 50

50 = 100

43 = X

43 x 100/50 = X

86 = X

Bird:

83 + 17 = 100

100 = 100

83 = X

83 x 100/100 = X

83 = X

Therefore, the dolphin statue is 86% copper, while the bird statue is 83% copper, making the dolphin sculpture more coppery.

so, converting firstly the mixed fractions to improper fractions and then "adding".