10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it is bent in the form of a square, find the side of the square.

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--- radius

-- Length of the square

Step-by-step explanation:

Given

Solving (a): Find the radius (when it formed a circle).

The length of the wire represents the circumference (C) of the wire.

So, we have:

Make r the subject

Substitute 264 for C

Take as 22/7

Solving (b): Find the side length (when it formed a square).

The length of the wire represents the perimeter (P) of the wire.

So, we have:

Make L the subject

Substitute 264 for P

it has 4

step-by-step explanation:

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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