Need help with this
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Let n be the larger integer and n-2 be the smaller integer.

n² - (n - 2)²

= n² - (n - 2)(n - 2)

= n² - (n² - 4n - 4)

= n² - n² + 4n + 4

= 4n + 4

= 4(n + 1)

No matter what value n is, it will always be a multiple of 4.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

answer: hey there,

the answer you are looking for is a..

hope this you!