one card from a deck of cards is selected, it is replaced, and another card is chosen. what is the probability that the first card is a red card and the second card is a diamond card?​

the probability of a red card is 1/2 of 50% chance. The chance of a diamond card is 1/4 or 25% chance

Step-by-step explanation:

Answer as a fraction = 1/8

Answer in decimal form = 0.125

Answer as a percentage = 12.5%

Explanation:

The probability of choosing a red card is 1/2 since half of the cards are red (the other half are black).

This card is selected and then put back into the deck. This means that the second selection will deal with the same number of total cards.

Since we have four suits, and one of those suits is diamonds, this means the probability of choosing a diamond card is 1/4.

We then multiply the fractions to get (1/2)*(1/4) = (1*1)/(2*4) = 1/8

The probability of getting a red card first, then a diamond card second, is 1/8

Use your calculator to find that 1/8 = 0.125 which converts to the percent form 12.5%

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb