What is the are of point ABCD if there coordinats are (A, 1 1/2, 1) (B, 1 1/2, 6 1/3) (C, 5 1/2, 6 1/3) (D, 5 1/2, 1)

The answer is below

Step-by-step explanation:

What is the area of ABCD if the coordinates of the vertices are A (1 1/2, 1) = (3/2, 1),  B(1 1/2, 6 1/3) = (3/2, 19/3), C(5 1/2, 6 1/3) = (11/2, 19/3) and D = (5 1/2, 1) = (11/2, 1). Hence A(3/2, 1), B(3/2, 19/3), C(11/2, 19/3) and D(11/2, 1)

Therefore from the vertices, we can see that ABCD is a rectangle.

Area of ABCD = AB * BC

The distance between two points in the coordinate plane is given by:

Therefore:

Area of ABCD = AB * BC = 16/3 units * 4 units = 64/3 unit²

so, converting firstly the mixed fractions to improper fractions and then "adding".