The length of a recatangular garden is three feet more than four times the width. Find the perimeter and area of the garden.

The perimeter is (6+10b) and the area of the garden is (3b+4b²).

Step-by-step explanation:

Let l be the length and b be the width of the rectangle.

According to the question,

The length of a rectangular garden is three feet more than four times the width i.e.

l = 3+4b

The perimeter of a rectangle is given by :

P = 2(l+b)

Substitute all the values,

P = 2(3+4b+b)

P = 2(3+5b)

P = 6+10b

The area of a rectangle is given by :

A = lb

Substitute all the values,

A = (3+4b)b

A = 3b+4b²

So, the perimeter is (6+10b) and the area of the garden is (3b+4b²).

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.