A STADIUM HAS 15,600 SEATS. IT HAS 60 ROWS OF SEATS ALTOGETHER. THE 35 ROWS AT THE BACK HAVE 300 SEATS EACH. THE REST OF THE ROWS AT THE FRONT HAVE THE SAME NUMBER OF EACH SEATS EACH. HOW MANY SEATS ARE THERE IN EACH OF THE ROWS AT THE FRONT

The number of seats in each of the rows at the front =204

Step-by-step explanation:

Let x = The number of seats in each of the rows at the front.

Given: Total seats = 15,600

Total rows = 60

Rows in back = 35

Rows in front = 60-35=25

Total seats in front = 25x

Each row in the back has 300 seats.

Total seats in the back =300 x35=10500

Seats in front = 15600-10500=5100

i.e.

Hence, the number of seats in each of the rows at the front =204

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

146%

step-by-step explanation: