Keith is 5 years older than Trina. Two times the sum of their ages is 62. Write and solve an equation to find Keith’s age.

Trina is 13

Kieth is 18

Step-by-step explanation:

x + 5 = Kieth's age

Divide by 2 to separate the ages:

62 ÷ 2 = 31

Subtract the difference in ages:

31 - 5 = 26

Add the 5 years to Kieth's age:

31 + 5 = 36

Divide by 2 again, to eliminate the twice of their ages

26 ÷ 2 = 13

36 ÷ 2 = 18

Trina is 13

Kieth is 18

This is what i got. Sorry if i'm wrong, lmk if i am!

Hope this helps! Brainliest if i'm correct!?

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5