Four horses are pulling a wagon. each horse drinks 45,000 milliliter of water each day. how many liters of water will the horses drink in 5 days

900 liters

Step-by-step explanation:

Given : Four horses are pulling a wagon.

Each horse drinks 45,000 milliliter of water each day.

We know that 1 liter = 1000 milliliters

Then, 1 milliliter= liter

⇒45,000 milliliters =   liters

i.e. Each horse drinks 45 liters of water each day.

Then, amount of water drunk by 4 horses each day =

⇒ Amount of horses will drink in 5 days =

Hence, the horse will drink 900 liters of water in 5 days.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950