Trying to figure out how to solve the problem​

8√0.2

Step-by-step explanation:

using Pythagoras Therom

(68)^2 = (60)^2 + (x)^2

4624 = 3600 + x^2

4624/3600 = x^2

1.28 = x^2

√1.28 = x

x = 8√0.02

; )

step-by-step explanation: ; )

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb