A 7th grade classis selling packages of cotton candy at a festival for $2.95 each. Each package costs them $0.95 to make. They expect to sell between 900 and 1,000 packages of cotton candy during the festival. What is a reasonable estimate of the class’s profit? A. $900
B. $1,000
C. $2,000
D. $3,000

Answer C.

Step-by-step explanation:

The class sells them for $2.95, assuming $0.95 manufacturing cost per, leaving $2.00 profit per bag. If they sell 900-1000 packages at $2.00, it leaves $1800-$2000 profit.

if you see they have 2.95 and 0.95 you need to combert to a decimal and then you need to subtract 900 and 1,000

Step-by-step explanation:

and oviosly is a 900

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,