1. The quadrilateral JKLM is shown below. y KA 5 If this quadrilateral is reflected over the y-axis, what rule was followed for the new vertices? A (x, y) - (x,-Y) B (x, y) - (x, y) → (-x, y) C (x, y) = (x, y) D (x, y) (-X,-Y) is it a positive x or a negative and is a a positive y or a negative?​

7

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: