If you answer this question correctly I will answer 1 of your questions Evaluate the expression 10−5a+(18−b), where a=2 and b=11.

Which THREE expressions will have the same value?

28÷(a×2)

20+b−(4×a)

49−43+(a÷a)

30−25+(b−9)

50÷a−(b+20)

We can start by solving for 10-5a+(18-b). By plugging in a and b, we get

10 - 10 + (18 - 11)= 7

28 ÷ (a × 2) = 28/4 = 7

20 + b − (4 × a) = 31 - 8 = 23

49 − 43 + (a ÷ a) = 49 - 43 + 1 = 7

30 − 25 + (b − 9) = 5 + 2 = 7

50 ÷ a − (b + 20) = 25 - 31 = -6

So, 28 ÷ (a × 2), 49 − 43 + (a ÷ a), and 30 − 25 + (b − 9) will all have the same answer as 10−5a+(18−b)

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

step-by-step explanation: