Isabel has just started a photo-sharing website and she is preparing for a presentation for an investor. Her site has 150 users and is growing by 25 users per day. Her competitor's site has 600 users and is growing by 10 users per day.

See Explanation

Step-by-step explanation:

Your question isn't well analysed but I guess that you want to calculate when both of them will have same number of users.

Let the number of days that both of them will have thesame number of competitors be x.

Therefore,

150 + 25x = 600 + 10x

25x - 10x = 600 - 150

15x = 450

x = 450/15

x = 30

They'll have same competitors by the 30th day.

The number of competitors will be:

= 150 + 25x

= 150 + 25(30)

= 150 + 750

= 900

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

don't give

take it once

try and try and you will not

happy to

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