Mathematics, 12.02.2021 02:10 karyn3853
A rectangular garden has an area of 40 square feet.
The length of the garden is 3 feet less than its width.
Write an equation to determine the length and width of the garden.
What are the dimensions of the garden?
Answers: 1
Mathematics, 21.06.2019 16:30, angeline310
Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
Answers: 2
Mathematics, 22.06.2019 03:30, Issaking0131
Paul needs to buy 5/8 pound of peanuts. measure a pound into sixteenths. what measure is equivalent to 5/8 pound
Answers: 1
A rectangular garden has an area of 40 square feet.
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