I need help with these questions. Please show workings.​

see explanation

Step-by-step explanation:

∠ AOB = 360° - 264° = 96°

The altitude OM bisects ∠ AOB and the base AB

(a)

∠ MOB = 0.5 × 96° = 48°

Using the cosine ratio in right triangle MOB

cos48° = = = ( OB is the radius r of the circle )

Multiply both sides by r

r × cos48° = 18 ( divide both sides by cos48° )

r = ≈ 27 cm ( to the nearest cm )

(b)

Using the tangent ratio in the right triangle MOB

tan48° = = = ( multiply both sides by 18 )

18 × tan48° = MB then

AB = 2 × MB = 2 × 18 × tan48° = 36 × tan48° ≈ 40 cm ( to nearest cm )

a

step-by-step explanation:

given the 2 equations

- x + y = - 2 → (1)

2x - 3y = 4 → (2)

multiplying (1) by 2 and adding to (2) will eliminate the x- term

- 2x + 2y = - 4 → (3)

add (2) and (3) term by term

(2x - 2x) + (- 3y + 2y) = (4 - 4), simplifying gives

- y = 0 ⇒ y = 0

substitute y = 0 in either of the 2 equations for corresponding value of x

substituting in (2) gives

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 0 ) → a