The Statistical Abstract of the United States reported that the average cost per day of owning an automobile in the United states is $7.62. This includes the cost of the car, general maintenance, gasoline, and insurance. A researcher claims that college students' average daily ownership expenses are less than the national average. A random sample of 54 college students who own cars found the average cost per day to be $6.78 with standard deviation $1.77. Use a 5% level of significance to test the claim that a college student's average daily ownership expenses are less than the national average. State the Null and Alternate Hypotheses, calculate the test statistic, compute the P value for this test, state the alpha value, then state your conclusion. Is there enough evidence to support the claim?

Step-by-step explanation:

The null and the alternative can be computed as:

The critical value for a left-tailed test at = -1.645

The test statistics can be computed as:

The P-value = (Z< -3.487)

The P-value = 0.00024

Decision Rule: TO reject at , if test statistics is less than the critical value (left tailed)

Conclusion: We reject   at ∝ = 5%, thus there is enough evidence to support the claim that the college students average daily ownership expenses are less than the national average.

answear:

a

step-by-step explanation: a

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all