US Weekly magazine claims that 32% of its readers believe Angelina Jolie was best dressed at the Academy awards. To verify this claim, how large a sample is needed for a 0.05 margin of error at a 95% confidence level?

335

Step-by-step explanation:

Formula for sample size :

, where p =population proportion, z* = critical z-value, E = Margin of error.

Given: p = 32% = 0.32

E = 0.05

Critical z-value for 95% confidence = 1.96

Required sample size :

Hence, the required sample size = 335

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

on friday there were 15 birds