PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x  = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y  = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

think about it deeply and passionately about this property

i am sorry

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2