I need help with this math please

question 1: it is between 8 and 9. question 2: option B.

Step-by-step explanation:

1. since the closest value that IS a squarable number is 64, the square root of 64 is 8. because 66 is greater than 64, we can estimate that the square root of 66 is between 8 and 9.

2. to solve this, we can take the square root of the numbers to begin.

the square root of 25 is 5 (because 5x5=25)

the square root of 16 is 4

20 is actually not squarable, so we can estimate that it is a little greater 4.

the answer would be √16, √20, 4.85, √25

it would be option b.

hope this helps!! :))

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752